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Question:
Published on: 3 December, 2024

Bresenham's Line Algorithm.

Answer:

This algorithm is used for scan converting a line. It was developed by Bresenham. It is an efficient method because it involves only integer addition, subtractions, and multiplication operations. These operations can be performed very rapidly so lines can be generated quickly.

In this method, next pixel selected is that one who has the least distance from true line.

The method works as follows:

Assume a pixel P1'(x1',y1'),then select subsequent pixels as we work our may to the night, one pixel position at a time in the horizontal direction toward P2'(x2',y2').

Once a pixel in choose at any step

The next pixel is

  1. Either the one to its right (lower-bound for the line)
  2. One top its right and up (upper-bound for the line)

The line is best approximated by those pixels that fall the least distance from the path between P1',P2'.

Bresenham's Line Algorithm

To chooses the next one between the bottom pixel S and top pixel T.
            If S is chosen
            We have xi+1=xi+1       and       yi+1=yi
            If T is chosen
            We have xi+1=xi+1       and       yi+1=yi+1

The actual y coordinates of the line at x = xi+1is
            y=mxi+1+b

Bresenham's Line Algorithm

The distance from S to the actual line in y direction
            s = y-yi

The distance from T to the actual line in y direction
            t = (yi+1)-y

Now consider the difference between these 2 distance values
            s - t

When (s-t) <0 ⟹ s < t

The closest pixel is S

When (s-t) ≥0 ⟹ s < t

The closest pixel is T

This difference is
            s-t = (y-yi)-[(yi+1)-y]
                    = 2y - 2yi -1

            Bresenham's Line Algorithm

Substituting m by Bresenham's Line Algorithm and introducing decision variable
                di=△x (s-t)
                di=△x (2 Bresenham's Line Algorithm (xi+1)+2b-2yi-1)
                        =2△xyi-2△y-1△x.2b-2yi△x-△x
                di=2△y.xi-2△x.yi+c

Where c= 2△y+△x (2b-1)

We can write the decision variable di+1 for the next slip on
                di+1=2△y.xi+1-2△x.yi+1+c
                di+1-di=2△y.(xi+1-xi)- 2△x(yi+1-yi)

Since x_(i+1)=xi+1,we have
                di+1+di=2△y.(xi+1-xi)- 2△x(yi+1-yi)

Special Cases

If chosen pixel is at the top pixel T (i.e., di≥0)⟹ yi+1=yi+1
                di+1=di+2△y-2△x

If chosen pixel is at the bottom pixel T (i.e., di<0)⟹ yi+1=yi
                di+1=di+2△y

Finally, we calculate d1
                d1=△x[2m(x1+1)+2b-2y1-1]
                d1=△x[2(mx1+b-y1)+2m-1]

Since mx1+b-yi=0 and m = Bresenham's Line Algorithm, we have
                d1=2△y-△x

Advantage:

1. It involves only integer arithmetic, so it is simple.

2. It avoids the generation of duplicate points.

3. It can be implemented using hardware because it does not use multiplication and division.

4. It is faster as compared to DDA (Digital Differential Analyzer) because it does not involve floating point calculations like DDA Algorithm.

Disadvantage:

1. This algorithm is meant for basic line drawing only Initializing is not a part of Bresenham's line algorithm. So to draw smooth lines, you should want to look into a different algorithm.

Bresenham's Line Algorithm:

Step1: Start Algorithm

Step2: Declare variable x1,x2,y1,y2,d,i1,i2,dx,dy

Step3: Enter value of x1,y1,x2,y2
                Where x1,y1are coordinates of starting point
                And x2,y2 are coordinates of Ending point

Step4: Calculate dx = x2-x1
                Calculate dy = y2-y1
                Calculate i1=2*dy
                Calculate i2=2*(dy-dx)
                Calculate d=i1-dx

Step5: Consider (x, y) as starting point and xendas maximum possible value of x.
                If dx < 0
                        Then x = x2
                        y = y2
                          xend=x1
                If dx > 0
                    Then x = x1
                y = y1
                        xend=x2

Step6: Generate point at (x,y)coordinates.

Step7: Check if whole line is generated.
                If x > = xend
                Stop.

Step8: Calculate co-ordinates of the next pixel
                If d < 0
                    Then d = d + i1
                If d ≥ 0
          Then d = d + i2
                Increment y = y + 1

Step9: Increment x = x + 1

Step10: Draw a point of latest (x, y) coordinates

Step11: Go to step 7

Step12: End of Algorithm

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