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Question:
Published on: 13 November, 2024

For the circuit shown below, find the potential difference between a and d:

Answer:

Fig. 6(a)

Applying KVL in 1st mesh, we have

4I1-3=0

Or I1=3/4 Amp.

Vab=2I1=2×3/4=3/2 V

Applying KVL at mesh 2nd, we have</p

10I2-5=0

I2=1/2 Amp.

Vcd=5I2=5×1/2=5/2 V

Now Vad=Vab+Vbc+Vcd=3/2-2+5/2=2 V

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