Find VAB from the circuit if all the resistances are of same value of 1 Ω.
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Fig. 20(a)
Redraw the Fig. 20(a), we have
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Fig. 20(b)
The resistance P and Q are in Series, the equivalent resistance R1=1+1=2Ω
The resistance R1 and R are in parallel. The equivalent resistance R2=(2×1)/(2+1)=2/3 Ω
Similarly the resistance U and T are in series and equivalent resistance R3=1+1=2 Ω.
The resistance R2 and s are in series and equivalent resistance R4=2/3+1=5/3 Ω. Finally the resistance R3 and R4 are in parallel each other. Hence total resistance between terminal A and B is
RTot=(5/3×2)/(5/3+2)=10/11 Ω
Hence VAB=1×10/11=10/11 Amp.
For the circuit shown bellow, determine the current i1,i2,i3 using nodal analysis
A flux of 0.0006Wb is required in the air – gap of an iron ring of cross – section 5.0 cm2and mean length 2.7 m with an air – gap of 4.5 mm. Determine the ampere turns required. Six H values and corresponding B values are noted from the magnetization curve of iron and given below.
H(At/m) |
200 |
400 |
500 |
600 |
800 |
1000 |
B(Wb/m2) |
0.4 |
0.8 |
1.0 |
1.09 |
1.17 |
1.19 |
What is meant by hysteresis in a magnetic circuit? What is the significance of B-H curve?
Describe why modulation is necessary for communication.
State Ampere’s Circular law.
Discuss the operating principle of Faraday’s rotation isolator.
What is strip line?
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Fig.22(a)