An air filled rectangular waveguide of inside dimensions 7 X 3.5 cm2oprtates in the dominant mode TE10
The cut-off frequency in the dominant mode is
\(f_c=\frac{c}{2a}=\frac{3\times{10}^8}{2\times7\times{10}^{-2}}=2.14\ GHz\)
The guide wavelength is
\(\lambda_g=\frac{\lambda}{\sqrt{1-\left(\frac{f_c}{f}\right)^2}} = \frac{3\times{10}^8/3.5\times{10}^9\ }{\sqrt{1-\left(\frac{2.14}{3.5}\right)^2}} = \frac{0.0857}{0.791}=10.83\) cm
Explain how high value of VSWR can be measured by the double minimum method.
What is IMPATT diode? How does the negative resistance arise in this diode?
State Ampere’s Circular law.
What is meant by entropy of a source?
What are the difference between TED’s and junction device?
Write short notes on:
Compare AM and NBFM.
