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Question:
Published on: 22 June, 2022

Derive an expression for the resonant frequency of a parallel circuit, one branch consisting of a coil of inductance L and resistance R and the other branch of capacitance C.

Answer:

Fig. 19

The series RL circuit with parallel C is given in Fig. 19. The designed circuit consists of resistance R, inductance L are in series with parallel configuration of capacitance C. Let us consider the current I flowing through the RLC circuit by the a.c. voltage source with constant value of V.

The current in the circuit

\(I=I_1+I_C\)

\(I=\frac{V}{R+j\omega L}+jV\omega C\)

\(I=V\left[\frac{1}{R+j\omega L}+j\omega C\right]\)

\(I=V\left[\frac{(R-j\omega L)}{R^2+{(\omega L)}^2}+j\omega C\right]\)

\(I=V\left[\frac{R}{R^2+{(\omega L)}^2}+j\left(-\frac{\omega L}{R^2+{(\omega L)}^2}+\omega C\right)\right]\)

Here at the resonance

\(\frac{\omega L}{R^2+{(\omega L)}^2}=\omega C\)

Or \(R^2+{(\omega L)}^2=\frac{L}{C}\)

Or \({(\omega L)}^2=\frac{L}{C}-R^2\)

\(\omega L=\sqrt{\frac{L}{C}-R^2}\)

The resonance frequency of the RLC circuit is \(f_0=\frac{1}{2\pi L}\sqrt{\frac{L}{C}-R^2}\)

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