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Question:
Published on: 24 July, 2024

For a broadcast super heterodyne AM receiver having no RF amplifier, the loaded quality factor Q of the antenna coupling circuit is 100. Now if the intermediate frequency is 455 KHz, then determine the image frequency and its rejection ratio at an incoming frequency of 1 MHz.

Answer:

Given that quality factor Q = 100

The intermediate frequency fi = 455KHz

Incoming frequency fs = 1MHz

The image frequency fsi = fs + 2fi = 1 × 106 + 2 × 455 × 103 = 1910KHz

Again we know that the relation

The image frequency rejection ratio

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