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Question:
Published on: 22 December, 2024

The maximum deviation allowed in an FM broadcast system is 75 kHz. If the modulating signal is a single tone sinusoid of 10 kHz, find the bandwidth of the FM signal. What will be the change in the bandwidth, if the modulating frequency is double? Determine the bandwidth when modulating signal amplitude is also double.

Answer:

Given that ∆f=75KHz and fm=10KHz

According to the Carson’s thumb rule the bandwidth

BW=2(∆f+fm )=2(75+10)=170KHz

The frequency deviation ∆f=kf Am

Then Bandwidth BW=2(kf Am+fm )

Modulation index β=∆f/fm =75/10=7.5

If the modulating frequency is double then the bandwidth

BW=2(∆f+2×fm )=2(75+2×10)=190KHz

Hence the frequency band (BW) is enhanced by (190-170)=20KHz

 

If the signal amplitude is doubled with normal modulating frequency then

BW=2(2kf Am+fm )

BW=2(2∆f+fm )=2(2×75+10)=320KHz

The bandwidth is enhanced by (320-170)=150KHz

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