Given that Pc = 10kW
Modulation index µ = 0.4
Total transmitted power
\[ P_t = P_c \left(1 + \frac{\mu^2}{2}\right) = 10 \times 10^3 \left(1 + \frac{0.16}{2}\right) = 10.8 \, \text{kW} \]
Now the effective modulation index
\[ m_a = \sqrt{m_{a1}^2 + m_{a2}^2} = \sqrt{0.16 + 0.09} = 0.5 \]
The total radiated power
\[ P_t = P_c \left(1 + \frac{m^2}{2}\right) \]
\[ P_t = P_c \left(1 + \frac{0.25}{2}\right) = 10 \times 10^3 \times 1.125 \]
Hence Pt = 11.25kW
Hence modulated carrier power is increased by amount of 11.25 - 10.08 = 1.17kW