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An AM transmitter has an un-modulated carrier power of 10 kW. It can be modulated by a sinusoidal modulating voltage to a maximum depth of 40%, without overload. If the maximum modulation index is reduced to 30%, what is the extent up to which the modulated carrier power can be increased without overloading?

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Ans

Given that P_c= 10kW

Modulation index µ = 0.4

Total transmitted power

$P_{t} = P_{c} (1 + \frac{μ^{2}}{2}) = 10 \times 10^{3} (1 + \frac{0.16}{2}) = 10.8 kW$

Now the effective modulation index

$m_{a} = \sqrt{m_{a 1}^{2} + m_{a 2}^{2}} = \sqrt{0.16 + 0.09} = 0.5$

The total radiated power

$P_{t} = P_{c} (1 + \frac{m^{2}}{2})$

$P_{t} = P_{c} (1 + \frac{0.25}{2}) = 10 \times 10^{3} \times 1.125$

Hence P_t = 11.25kW

Hence modulated carrier power is increased by amount of 11.25 - 10.08 = 1.17kW

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